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Ionic vs Covalent bonding Explained

What is ionic bonding?

Ionic bonding is the strong electrostatic force of attraction between oppositely charged ions. Ions are formed when atoms gain electrons or lose electrons.

When atoms gain electrons, they become negatively charged particles or ions; these ions are called anions.

When atoms lose electrons, they become positively charged particles or ions; these ions are called cations.

Fig.1 – diagram shows ionic bond formation between Lithium and Fluorine ions. The Lithium ion forms when the Lithium atom loses 1 electron. This electron is given to the Fluorine atom. As a result, the Fluorine atom becomes a Fluorine ion.

Illustration showing the formation of lithium fluoride (LiF) from lithium (Li) and fluorine (F) atoms. The top section depicts the atomic structure of Li and F, while the bottom section displays the resulting Li+ and F- ions.

What is covalent bonding?

A covalent bond is formed when two non-metal atoms share a pair of electrons. The shared electrons would usually be in the outer shells of the atoms.

Fig.2 – diagram shows covalent bond formation between two hydrogen atoms where each hydrogen atom shares a pair of electrons. A hydrogen molecule, H2 , is formed.

Diagram illustrating the formation of a hydrogen molecule (H2) from two hydrogen atoms, showing atomic structure and bonding.

Key differences between ionic and covalent bonding

Comparison table of ionic and covalent bonding characteristics.

Practice questions

A worksheet page from a chemistry resource discussing methane and buckminsterfullerene, with questions about their properties and structure.
An educational image showing the structure of graphite with carbon atoms linked in a diagrammatic form and a question about the number of covalent bonds each carbon atom forms.
Diagram illustrating the crystal structure of diamond, showing carbon atoms and their bonding arrangement.
An examination sheet featuring questions about carbon and its compounds, with diagrams labelled A, B, C, and D representing different carbon structures such as graphite and poly(ethene). Figure 2 depicts the structure of diamond, with carbon atoms illustrated in a specific arrangement.
A science exam question asking students to describe the reaction between magnesium and oxygen, specifically referencing electrons.

Reference link:

2.1 Chemical Bonds – Ionic, Covalent and Metallic (F) QP.pdf

Practice answers

A mark scheme for a chemistry exam covering ionic, covalent, and metallic bonds, detailing answers for various questions.
An exam question sheet on chemical bonds, featuring multiple-choice options and calculations related to ionic, covalent, and metallic bonds.
Diagram explaining ionic bonding, focusing on magnesium losing electrons and oxygen gaining electrons to form ions.

Reference link:

2.1 Chemical Bonds – Ionic, Covalent and Metallic (F) MS.pdf

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Biology Chemistry Science

Photosynthesis Explained Step-by-Step (GCSE Biology)

What is photosynthesis?

Photosynthesis is a chemical process by which plants convert carbon dioxide and water into glucose and oxygen using light energy from the Sun. Photosynthesis occurs in the chloroplasts found in plant cells.

The photosynthesis equation

Here is the chemical equation for photosynthesis:

Limiting factors

A limiting factor is a factor that affects the rate of photosynthesis of a plant.

Limiting factors in photosynthesis are:

  • light intensity
  • the concentration of carbon dioxide
  • the temperature of its surroundings.

Example GCSE exam question

Source:

4.1 Photosynthesis (F) QP.pdf

Source:

4.1 Photosynthesis (F) MS.pdf

Link to more papers using GCSE AQA Biology:

AQA GCSE Biology Topic 4: Bioenergetics Revision – PMT

Categories
Chemistry Science

Understanding Chemical Equations

What chemical equations represent

Scientists use symbols in chemical equations to show what reactant(s) and product(s) are involved in a chemical reaction, what direction the reaction proceeds in, what physical states the reactant(s) and product(s) are in and what reaction conditions are involved (e.g. temperature, presence of a catalyst, time etc). This helps scientists to understand chemical equations and how to apply the equation practically if they want to carry out the reaction to obtain a product (or group of products) for commercial and research purposes.

Step-by-step balancing method with chemical equation example 1

Step 1) Here is an example of the combustion of methane, CH4 , which is an unbalanced equation:

CH4​(g) + …O2​(g) → CO2​(g)+ …H2​O(l)

(g) means the physical state of the chemical is in a gaseous state while (l) means the physical state of the chemical is in a liquid state. So methane, oxygen and carbon dioxide are in a gaseous state while water is in a liquid state.

The small number 4, which is called subscript 4, from CH4 , means there are four Hydrogen atoms covalently bonded to a Carbon atom.

Subscript 2 from O2 means there are two Oxygen atoms covalently bonded to each other.

Subscript 2 from CO2 means there are two Oxygen atoms each covalently bonded to a Carbon atom.

Subscript 2 from H2O means there are two Hydrogen atoms each covalently bonded to an Oxygen atom.

Step 2)

Next step I would do to balance the chemical equation is I would list the type of atoms and their number on the left hand side (LHS) of the equation and on the right hand side (RHS) of the equation.

CH4​(g) + …O2​(g) → CO2​(g)+ …H2​O(l)

Step 3)

I can see on the LHS there are 4 hydrogen atoms while on the RHS there are 2 hydrogen atoms. We can’t change subscript 2 on H2​O to subscript 4 due to the way 2 hydrogen atoms are each bonded to an oxygen atom, we can instead double the number of water molecules to get 4 hydrogen atoms on the RHS. When we double the number of water molecules on the RHS, we also increase the number oxygen atoms on the RHS as well to get 4 oxygen atoms.

Step 4)

The last step is to now double the number of oxygen atoms on the LHS to get a total of 4 oxygen atoms.

Step 5)

So now the the complete balanced equation is:

CH4​(g) + 2O2​(g) → CO2​(g)+ 2H2​O(l)

What this equation tells the scientist is that 1 mole of methane molecule will react with 2 moles of oxygen molecules to produce 1 mole of carbon dioxide and 2 moles of water molecules. If you don’t know what a mole is, click on the following link below:

Congratulations! If you have read this far and followed the steps without any difficulty, you have fully understood balancing the chemical equation for combustion of methane.

References:

Combustion of hydrocarbon fuels – Polluting the atmosphere – AQA – GCSE Chemistry (Single Science) Revision – AQA – BBC Bitesize

Categories
Science

What is a mole in chemistry explained simply

What is a mole?

Ever wondered what a mole is? A mole seems complicated but

1 mole = 6.02214076 × 1023 atoms, molecules, compounds or ions

Mole explained in simple terms

Think of 1 mole as a way to group a very large amount of atoms/ ions/ molecules/ compounds similar to how we group people e.g. 1 class = 30 students , 1 football team (on the pitch) = 11 players.

Mole and its relationship to atomic mass unit of an element

If you look at the Periodic Table for an element, for example Iron (symbol Fe), you will notice the number 55.845 which is its atomic mass number; atomic mass number is g/mol units and that means that if you want 1 mole of Iron, you will need 55.845 g of it.

Fig.1

Fig. 2

Fig. 3

Let’s take a look at another example which is Carbon-12. Carbon-12 (which has an atomic mass of 12 g/mol) helps to provide a concrete example of 1 mole because 12 grams of carbon-12 is equal to 1 mole of carbon atoms (think of coal as that is made mostly of carbon). Other substances will have different masses to make up 1 mole e.g. because a sodium atom has an atomic mass unit of 22.99 g/mol , you would need 22.99 g of sodium metal to make 1 mole of sodium atoms. Another example is calcium which has an atomic mass unit of 40.08 g/mol so you would need 40 g of calcium metal to make 1 mole of calcium atoms.

Fig. 4 – Picture showing 12g of carbon measured which is equivalent to 1 mole of carbon-12 atoms

Example of a past paper question involving moles

Let’s have a look at a past paper question example from PhysicsAndMathsTutor.com based on a GCSE AQA Chemistry past paper:

Below is an example Mark Scheme of how to solve it:

So in Step 1 of the mark scheme, we want to find out the number of molecules from 1 mole of carbon atoms, not from 70 carbon molecules so first step is to calculate 1÷70 = 0.0142857 moles.

Step 2:

if 1 mole = 6.02214076 × 1023 atoms

then

0.0142857 x 1 moles = 0.0142857 x 6.02214076 × 1023 atoms

0.0142857 moles = 8.6 x 1021 atoms